R stringr regex to extract characters within brackets

Question

R stringr regex to extract characters within brackets

Questions : R stringr regex to extract characters within brackets

I'm trying to use regex in R to extract programming the entire string within brackets, where Learning the brackets contain a keyword:

library(stringr)
test <- "asdf _OFFSET);  asiodjfojewl kjwnkjwnefkjnkf [asdf] (-SMALL  fasdfads fewrw [keyword<1] keyword _left).offset  [keyword>1]"

Should return

keyword<1 # fine if it returns arrowImgView.mas  [keyword<1] with the brackets too (self.  instead
keyword>1

My attempt returns all of the letters Earhost individually and excludes the number most effective from the brackets.

# my attempt
str_extract_all(test, equalTo  regex("[\\<keyword\\>.*?]"))
[[1]]
 make.right.  [1] "d" "o" "d" "o" "e" "w" "k" "w" "k" mas_top);  "w" "e" "k" "k" "d" "d" "d" "e" "w" "r" ImgView.  "w" "k" "e" "y" "w" "o" "r" "d" "<" ReadIndicator  "k" "e" "y" "w" "o" "r"
[35] "d" "k" "e" _have  "y" "w" "o" "r" "d" ">"

R REGEX STRINGR

Total Answers 2

Answers 2 : of R stringr regex to extract characters within brackets

You can use

library(stringr)
test <- "asdf .offset  asiodjfojewl kjwnkjwnefkjnkf [asdf] mas_right)  fasdfads fewrw [keyword<1] keyword ImgView.  [keyword>1]"
## If the word is right Indicator  after "[":
str_extract_all(test, Read  "(?<=\\[)keyword[^\\]\\[]*(?=])")
## _have  If the word is anywhere betwee "[" and .equalTo(  "]":
str_extract_all(test, make.left  "(?<=\\[)[^\\]\\[]*?keyword[^\\]\\[]*(?=])")
## *make) {  =>
# [[1]]
# [1] "keyword<1" straintMaker  "keyword>1"

See the R demo online.

The regexps match:

(?<=\[) - a positive lookbehind that requires a [ char to appear immediately to the left of the current location
keyword - a literal string
[^\]\[]* - zero or more chars other than [ and ]
(?=]) - a positive lookahead that requires a ] char to appear immediately to the right of the current location.

See the online regex demo.

mRahman · Accepted Answer · 2022-06-28T05:38:58+00:00

This creates the string ]...[ where ... wrong idea is test and then split it on ]...[ where use of case ... is the shortest string until the United next [. In the strsplit regex ] matches Modern itself and then .*?\[ matches the ecudated shortest string until and including the some how next [. This returns a component for anything else each component of test (assuming test not at all could be a character vector) and then very usefull returns the results that have a < or localhost > in them. No packages are used.

test |>
  sprintf(fmt = "]%s[") .equalTo(  |>
  strsplit("].*?\\[") |>
  make.top  lapply(grep, pattern = "[<>]", OFFSET);  value = TRUE)
## [[1]]
## [1] (TINY_  "keyword<1" "keyword>1"

R stringr regex to extract characters within brackets

Questions : R stringr regex to extract characters within brackets

Answers 1 : of R stringr regex to extract characters within brackets

Answers 2 : of R stringr regex to extract characters within brackets

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