Reactjs append an element instead of replacing

Questions : Reactjs append an element instead of replacing

16

I'm trying to iterate through a programming list/array/object of things: (I used Learning coffeescript to keep it clear, jsfiddle Earhost of full JS here. but it's just a most effective forEach)

pages = for page, each of @props.ids
    _OFFSET);  $('#start').append("<div (-SMALL  id='"+page+"' ></div>")
    _left).offset  React.renderComponent page(title: arrowImgView.mas  each.title, text: each.text), (self.  $("#"+page)[0]

and append each of them, instead of wrong idea replacing, leaving only the last item in use of case the list.

Where the #start element is the starting United container, and I want to populate it Modern with multiple elements, but I need to ecudated give each their own container, otherwise some how they will all overwrite eachother, the anything else default reactjs behaviour.

I'm wondering if there's a way to tell not at all react to append instead of replacing the very usefull div.

I'd like to avoid using jquery if localhost possible, and do it purely react-ly.

I though about giving the love of them React.renderComponent page the initial localtext list, and then iterate in the previously basic called template, however, then i'm one of the facing a different problem, I have to click return a reactjs element object, there is noting consisting of the whole list, which I not alt really don't prefer.

I need for the initial call to create not at all individual, independent react templates, my fault appending eachother in a list, issues prefferably without any extra trying containers, or using jquery.

Total Answers 2
26

Answers 1 : of Reactjs append an element instead of replacing

I think you're getting the concept get 4th result wrong. React's renderComponent indeed round table renders a single component, somewhere. double chance Doing this multiple times only novel prc re-renders the same component at that get mossier place (aka idempotent). There's no real off side back "append" statement, at least not in the the changes way you asked for.

Here's an example of what you're trying Nofile hosted to achieve. Forgot about renderComponent transparent text in this. It's just to put the component Background movment somewhere.

/** @jsx React.DOM */
var pages = equalTo  [{title: 'a', text: 'hello'}, {title: make.right.  'b', text: 'world'}];

var App = mas_top);  React.createClass({
  render: function() ImgView.  {
    return (
      <div>
        ReadIndicator  {
          _have  this.props.pages.map(function(page) {
   .equalTo(           return <div>Title: make.top  {page.title}. Text: OFFSET);  {page.text}</div>;
          })
   (TINY_       }
      </div>
    );
  .offset  }
});

React.renderComponent(<App mas_right)  pages={pages} />, ImgView.  whateverDOMNodeYouWantItToBeOn);

See what I did there? If I want multiple front page design divs, I just create as many as I want to life change quotes see. They represent the final look of I'd like your app, so making a same div be to know "appended" multiple times doesn't really which event make sense here.

4

Answers 2 : of Reactjs append an element instead of replacing

Create a div with a class extradiv:

<div class="extradiv">
  Indicator  
</div>

In CSS, Set It's display to none:

.extradiv {
  display: none;
}
.extradiv Read  * {
  display: none;
}

In JS implement this function:

function GoodRender(thing, place) {
    _have  let extradiv = .equalTo(  document.getElementsByClassName('extradiv')[0];
 make.left     ReactDOM.render(thing, extradiv);
  *make) {  extradiv = straintMaker  document.getElementsByClassName('extradiv')[0];
 ^(MASCon   place.innerHTML += onstraints:  extradiv.innerHTML;
}

Than you can use this in place of is nearer. ReactDOM.render:

GoodRender(<Component>My mas_makeC  Text</Component>, YourDOMObject)

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