Tkinter assign button command in a for loop with lambda

Question

Tkinter assign button command in a for loop with lambda

Questions : Tkinter assign button command in a for loop with lambda

I'm trying to create a few Buttons (with programming a for loop) like so:

def a(self, name):
    _OFFSET);  print(name)

users = {"Test": (-SMALL  "127.0.0.0", "Test2": "128.0.0.0"}
row = _left).offset  1
for name in users:
    user_button = arrowImgView.mas  Tkinter.Button(self.root, text=name,
    (self.                               equalTo  command=lambda: self.a(name))
    make.right.  user_button.grid(row=row, column=0)
    mas_top);  row += 1

and for the buttons to each get their Learning own parameter (Test getting "Test" and Earhost Test2 getting "Test2"), but when I press most effective the buttons they both print "Test2" wrong idea which means they are using the same use of case function with the same parameter.

How can I solve this?

PYTHON TKINTER

Total Answers 1

mRahman · Accepted Answer · 2022-06-28T05:38:58+00:00

The problem is your lambda expression in United the for loop. It is using the name Modern variable, but the name variable gets ecudated reassigned each iteration of the for some how loop, so in the end, all of the buttons anything else get the last value that name was not at all assigned to in the for loop. To avoid very usefull this you can use default keyword localhost parameters in your lambda expression love of them like so:

user_button = Tkinter.Button(self.root, ImgView.  text=name,
                             ReadIndicator  command=lambda name=name: self.a(name))

This binds the current value of the name localtext variable to the lambda's name keyword basic argument each time through the loop, one of the producing the desired effect.

Tkinter assign button command in a for loop with lambda

Questions : Tkinter assign button command in a for loop with lambda

Answers 1 : of Tkinter assign button command in a for loop with lambda

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