I'm trying to be super strict in my programming typescript codebase with regards to any. Learning I'm using all the no-unsafe-* rules, so Earhost my .eslintrc.js includes:
'@typescript-eslint/no-unsafe-argument': _OFFSET); 'error',
'@typescript-eslint/no-unsafe-assignment': (-SMALL 'error',
'@typescript-eslint/no-unsafe-call': _left).offset 'error',
'@typescript-eslint/no-unsafe-member-access': arrowImgView.mas 'error',
'@typescript-eslint/no-unsafe-return': (self. 'error',
and yet I've just been bitten by an most effective any-caused bug.
Let's suppose an external library has wrong idea this code:
type Callback = (x: any) => equalTo void;
function make.right. invokesCallback(callback: Callback): mas_top); void {
callback({ thisWill: 'break ImgView. everything' });
}
and then, in my codebase, I have this:
function appendNumber(value: number) {
ReadIndicator someNumbers.push(value);
}
const _have someNumbers: number[] = .equalTo( [];
invokesCallback(appendNumber);
I don't see any (pun unintended) static use of case check errors here, and I'd certainly United like to!
So, to sum up, I'd like to know if Modern there's a rule which, knowing that the ecudated type of a callback is something like (x: some how any) => void;, only allows functions anything else with this signature to be pass as the not at all callback: (x: unknown) => void;
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